can aokiji walk on water?

Aokiji’s Ice Age creates an ice bridge across the sea, so that Tonjit can find his traveling village of people. His people are three islands away, but technically this string of islands is one large island that gets covered by tide for most of the year. Once per year, however, the tide lowers and he can travel to the next island, but…

He needs a horse to make it in time to beat the tide for crossing to one island. The switch from low tide to high tide lasts 6 hours and 12.5 minutes. Average human walking speed is 1.4 m/s.

6 hours and 12.5 minutes = 22,350 seconds

1.4 * 22,350 = 31,290 m, minimum distance between islands.

Aokiji freezes enough ocean so that Tonjit can cross three island’s worth, so…

31,290 * 3 = 93,870 m, total distance of Aokiji’s ice bridge

Sanji is 1.77 m tall here. He measures 45 pixels compared to the seak king’s eye at 18 and width of the observable ice bridge at 603.

18 / 45 = .4 * 1.77 = .708 m, sea king’s eye

603 / 45 = 13.4 * 1.77 = 23.718 m, width of ice bridge

Sea king’s eye is 22 pixels compared to height from fins to its belly at 302.

302 / 22 = 13.727 * .708 = 9.719 m, sea king height

Part of the sea king is completely submerged when Aokiji performs Ice Age, and noen of its fins stick out. I figure that makes for a good minimum depth for the frozen water. Otherwise, wouldn’t the sea king’s lower half be wriggling around?

Treating it as a very long rectangular prism, the volume of Aokiji’s ice bridge would be 21,638,465.767 m^3

Density of sea water near the surface is 1,026.6 Kg/m^3

21,638,465.767 * 1,026.6 = 22,214,048,956.402 Kg, mass of frozen seawater

When it comes to freezing, it’s best to think of it like a release of energy, as opposed to putting that energy into something like melting or vaporization. It is in fact the polar opposite of vaporizing, and yet, it requires the same level of energy to pull off.

We’ll have to use latent heat and specific heat capacity to figure out the energy required.

Let’s assume that the seawater is 20 degrees C. We’re figuring it out for minimum of freezing (0 C), so temp change is 20 C. Specific heat of seawater is 3,850 J/Kg C.

22,214,048,956.402 * 3,850 * 20 = 1,710,481,769,642,954 J

Latent Heat of Fusion of water/ice is 333,000 J/kg.

22,214,048,956.402 * 333,000 = 7,330,636,155,612,660 J

7,330,636,155,612,660 + 1,710,481,769,642,954 = 9,041,117,925,255,614 J, or 2.16 Megatons

Zoro Slices Some Cannonballs

The Franky Family makes a very poor decision in messing with the Straw Hats; demonstrated perfectly by Zoro slicing up their sneak attack cannonballs, and any hopes that had at winning in a fight. For this feat, I’ll be going with a cannonball muzzle velocity of 1,700 Ft/s or 518.16 m/s based on the cannonball’s sizes clearly being over 200 mm and 32 lbs.

Luffy is 1.72 m tall. He’s 24 pixels here compared to the floor tiles at 11.

11 / 24 = .458 * 1.72 = .788 m, length of each tile

We can see below that Zoro is roughly on the same horizontal plain as Sanji before the cannons fired.

Sanji is 11 tiles away from Zoro’s position after he’s through cutting the cannonballs.

11 * .788 = 8.668 m, distance traveled by Zoro

The cannonballs, comparatively, made it 3 tiles before Zoro got to them.

3 * .788 = 2.364 m, distance traveled by front cannonball

2.364 / 518.16 = .0046 s, time frame.

8.668 / .0046 = 1,884.348 m/s, or Mach 5.54

This is remarkably similar to the Yama feat from my previous blog post.

Usopp’s Flame Star

Usopp covers the battlefield in gas, then unleashes his Flame Star, which creates a large explosion. Really, this is more a testament to Luffy’s durability, as this move requires some setup for Usopp.

Usopp is 1.74 m tall. He measures 34 pixels here compared to fireball diameter at 681.

681 / 34 = 20.029 * 1.74 = 34.851 m, diameter of fireball

Using Taylor’s Law, we can figure out the explosive yield.

E = 8*pi*p*R^5 / [75(y-1)t^2]

Where p is density of the air, t is time after explosion has formed, R is radius of the explosion. y is specific heat ratio (Will be using 1.4 here as is common)

For time, I’ll be using the speed of the explosion. Due to the shockwave that reaches all the way to the Going Merry, I’ll be treating this as a high explosive. The minimum detonation velocity of a high explosive is 3,000 m/s.

34.851 / 2 = 17.426 m, radius of explosion.

17.426 / 3,000 = .0058 s, time frame.

8 * 3.14 * 1.2 * 17.426^5 / [75(1.4 – 1).0058^2] = 47,996,789,424.938 J, or 11.472 Tons of TNT

Franky’s Coup De Vent

Franky’s Coup De Vent dents the giant metal crane and destroys the galleon behind it. In addition, it causes the crane further back to tip over, but I have no way of quantifying that one.

I’ll be using an average Japanese male height of 1.70 m for the tiny specs near the crane. One such person measures at 4 pixels compared to the hole in the crane at 44.

44 / 4 = 11 * 1.70 = 18.7 m, length of hole

The hole measures at 44 pixels compared to one of the steel beams at 11, the length of the beams at 113, and the deflection of the beams at 42.

11 / 44 = .25 * 18.7 = 4.675 m, width and depth of steel beam

113 / 44 = 2.568 * 18.7 = 48.022 m, length of steel beam

42 / 44 = .955 * 18.7 = 17.86 m, length of bent beam

Using this handy calculator, I can figure out the amount of energy required to bend the steel beam to such a degree. Entering the figures in inches, the energy comes out to 35,572,497,905.787 J.

However, four of these beams are attached, so…

35,572,497,905.787 * 4 = 142,289,991,623.148 J, or 34.008 Tons of TNT

RESULTS

Aokiji’s Ice Age – 2.16 Megatons

Zoro Slices Cannonballs – Mach 5.54

Aokiji can freeze the water and as a result can freely walk on it.