Doran Zaillian

To find Ksp, we first need a chemical equation describing calcium hydroxide dissolving:

Ca(OH)2→Ca2++2OH-

We also need the rate law for this equation:

Kc=2/

The numerator in this rate law, 2, is Ksp. So we need to figure out what and are. We can find them since we have the molarity (same thing as solubility) of the calcium hydroxide, 1.11*10-2 mol/L. We always assume the chemical equation occurs in a 1 L solution, which makes the calculations easier. So, we are starting with 1.11*10-2 moles of Ca(OH)2. By looking at the coefficients in the equation (if not written then the coefficient is 1), we see that for every mole of Ca(OH)2 put in, we get 1 mole of Ca2+ as a product. Therefore the moles of Ca2+ obtained is the number of moles of Ca(OH)2 put in, 1.11*10-2. Since this is still happening in a 1 L solution, =1.11*10-2 mol/L. As for OH-, the equation says that for every mole of Ca(OH)2 put in, we get 2 moles of OH-. Therefore the moles of OH- obtained is 2 times the number of moles of Ca(OH)2 put in, or 2.22*10-2, and like with , =2.22*10-2 mol/L.

Therefore Ksp=(1.11*10-2)(2.22*10-2)2=5.5*10-6 (do not plug in any measurement units).

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