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Try this: have a lock in the module where your function is, and if the input to the function is such that locking is required, acquire the lock inside the function. Otherwise don't.

l = threading.RLock()""def fn(arg):"    if arg == arg_that_needs_lock:"        l.acquire()"        try:"            # do stuff"        finally:"            l.release()"    else:"        # do other stuff

EDIT:

As far as I can tell now, the question is actually about how to prevent any two threads from running the same function with the same argument at the same time. There's no problem with two threads running the same function with different arguments at the same time, though. The simple method to do this, if all valid arguments to the function can be dictionary keys, is to create a dictionary of arguments to locks:

import threading""dict_lock = threading.RLock()"locks = {}""def fn_dict(arg):"    dict_lock.acquire()"    try:"        if arg not in dict:"            locks[arg] = threading.RLock()"        l = locks[arg]"    finally:"        dict_lock.release()"    l.acquire()"    try:"        # do stuff"    finally:"        l.release()

If your function can be called with many different arguments, though, that amounts to a lot of locks. Probably a better way is to have a set of all arguments with which the function is currently executing, and have the contents of that set protected by a lock. I think this should work:

set_condition = threading.Condition()"current_args = set()""def fn_set(arg):"    set_condition.acquire()"    try:"        while arg in current_args:"            set_condition.wait()"        current_args.add(arg)"    finally:"        set_condition.release()"    # do stuff"    set_condition.acquire()"    try:"        current_args.remove(arg)"        set_condition.notifyAll()"    finally:"        set_condition.release()

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