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You could use a list comprehension or a generator expression instead:

', '.join([str(x) for x in list])  # list comprehension"', '.join(str(x) for x in list)    # generator expression

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Is it possible that the bytes got shuffled somehow? The arrangements of bits that you describe (sign bit in byte 2, LSB of exponent in byte 1) is different from Appendix O that you link to. It looks like byte 1 and 2 were exchanged.

I'll assume that byte 3 and 4 were also exchanged, so that the real hex value is 43D4DB93. This translates as 0100 0011 1101 0100 1101 1011 1001 0011 in binary, so the sign bit is 0, indicating a positive number. The exponent is 10000111 (binary) = 135 (decimal), indicating a factor of 2^(135-128) = 128. Finally, the mantissa is 0.1101 0100 1101 1011 1001 0011 (binary), using that Appendix O says that you have to add 0.1 in front, which is approximately 0.8314 in decimal. So your number is 0.8314 * 128 = 106.4 under my assumptions.

Added: Some Python 2 code might clarify:

input = 0xD44393DB;"reshuffled = ((input & 0xFF00FF00) >> 8) | ((input & 0x00FF00FF) << 8);"signbit = (reshuffled & 0x80000000) >> 31;"exponent = ((reshuffled & 0x7F800000) >> 23) - 128;"mantissa = float((reshuffled & 0x007FFFFF) | 0x00800000) / 2**24;"result = (-1)**signbit * mantissa * 2**exponent;

This yields result = 106.42885589599609.

Here is an explanation for the line computing the mantissa. Firstly, reshuffled & 0x007FFFFF yield the 23 bits encoding the mantissa: 101 0100 1101 1011 1001 0011. Then ... | 0x00800000 sets the hidden bit, yielding 1101 0100 1101 1011 1001 0011. We now have to compute the fraction 0.1101 0100 1101 1011 1001 0011. By definition, this equals 1*2^(-1) + 1*2^(-2) + 0*2^(-3) + ... + 1*2^(-23) + 1*2^(-24). This can also be written as (1*2^23 + 1*2^22 + 0*2^21 + ... + 1*2^1 + 1*2^0) / 2^24. The expression in brackets is the value of 1101 0100 1101 1011 1001 0011 (binary), so we can find the mantissa by dividing (reshuffled & 0x007FFFFF) | 0x00800000 by 2^24.

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